Digital Design Mano 3rd Edition Solution Manual Meriam
Digital Design By Morris Mano 3rd Edition Solution Manual
Digital Design Mano 3rd Edition Solution Manual Online

Digital Design Mano 3rd Edition Solution Manual Meriam

Digital Design By Morris Mano 3rd Edition Solution Manual

Digital Design (3rd Edition) Mano, M. Morris, Mano, Morris M on Amazon.com.FREE. shipping on qualifying offers. Digital Design (3rd Edition). Answers to selected problems appear in at the end of the book to aid the student and to help the independent reader. A solutions manual is available for the instructor from the publisher. Plz send the solution manual of morris mano 3rd edition Digital logic and design as soon as possible Re: Digital Design (3rd Edition) by M. Morris Mano solutions manual getsolution team. Digital Design 5th edition Mano Solution. Oct 13, 2012 Author Name: 1: M. MORRIS MANO 2: MICHAEL D. CILETT ISBN:, 881 Publisher: Prentice Hall, 2002 Edition: 3rd Edition Type: Solution Manual Size: 2. Digital Design -4th- Solution Manual - Mano (001) Book title Digital Design; Author. Morris; Ciletti Michael D. Digital Design -4th- Solution Manual - Mano - StuDocu Design Mano 5th Edition Solutions Digital Design, 5th Edition teaches the fundamental concepts of digital design in a clear, accessible manner. The text presents the.

Digital Design Mano 3rd Edition Solution Manual Online

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SOLUTIONS MANUAL
DIGITAL DESIGN
WITH AN INTRODUCTION TO THE VERILOG HDL Fifth Edition
M. MORRIS MANO Professor Emeritus California State University, Los Angeles
MICHAEL D. CILETTI Professor Emeritus University of Colorado, Colorado Springs
rev 02/14/2012
Digital Design With An Introduction to the Verilog HDL – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2012, All rights reserved.
Full file at https://testbankuniv.eu/Digital-Design-5th-Edition-Mano-Solutions-Manual
1
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CHAPTER 1 1.1
Base-10: Octal: Hex: Base-12
16 17 20 21 10 11 14 15
1.2
(a) 32,768
18 22 12 16
19 23 13 17
20 24 14 18
21 25 15 19
(b) 67,108,864 3
22 23 24 25 26 27 30 31 16 17 18 19 1A 1B 20 21
26 27 28 29 30 32 33 34 35 36 1A 1B 1C 1D 1E 22 23 24 25 26
31 37 1F 27
32 40 20 28
(c) 6,871,947,674
(4310)5 = 4 * 5 + 3 * 5 + 1 * 51 = 58010
1.3
2
(198)12 = 1 * 122 + 9 * 121 + 8 * 120 = 26010 1.4
1.5
(435)8 = 4 * 82 + 3 * 81 + 5 * 80 = 28510
(345)6 = 3 * 62 + 4 * 61 + 5 * 60 = 13710 16-bit binary: 1111_1111_1111_1111 Decimal equivalent: 216 -1 = 65,53510 Hexadecimal equivalent: FFFF16 Let b = base (a) 14/2 = (b + 4)/2 = 5, so b = 6 (b) 54/4 = (5*b + 4)/4 = b + 3, so 5 * b = 52 – 4, and b = 8 (c) (2 *b + 4) + (b + 7) = 4b, so b = 11
1.6
(x – 3)(x – 6) = x2 –(6 + 3)x + 6*3 = x2 -11x + 22 Therefore: 6 + 3 = b + 1m, so b = 8 Also, 6*3 = (18)10 = (22)8
1.7
64CD16 = 0110_0100_1100_11012 = 110_010_011_001 _101 = (62315 )8
1.8
(a) Results of repeated division by 2 (quotients are followed by remainders): 43110 = 215(1); 107(1); 53(1); 26(1); 13(0); 6(1) Answer: 1111_10102 = FA16
3(0)
1(1)
(b) Results of repeated division by 16: 43110 = 26(15); 1(10) (Faster) Answer: FA = 1111_1010 1.9
(a) 10110.01012 = 16 + 4 + 2 + .25 + .0625 = 22.3125 (b) 16.516 = 16 + 6 + 5*(.0615) = 22.3125 (c) 26.248 = 2 * 8 + 6 + 2/8 + 4/64 = 22.3125 (d) DADA.B16 = 14*163 + 10*162 + 14*16 + 10 + 11/16 = 60,138.6875
Digital Design With An Introduction to the Verilog HDL – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2012, All rights reserved.
Full file at https://testbankuniv.eu/Digital-Design-5th-Edition-Mano-Solutions-Manual
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(e) 1010.11012 = 8 + 2 + .5 + .25 + .0625 = 10.8125
1.10
(a) 1.100102 = 0001.10012 = 1.916 = 1 + 9/16 = 1.56310 (b) 110.0102 = 0110.01002 = 6.416 = 6 + 4/16 = 6.2510
1.11
Reason: 110.0102 is the same as 1.100102 shifted to the left by two places.
1011.11 101 | 111011.0000 101 01001 101 1001 101 1000 101 0110 The quotient is carried to two decimal places, giving 1011.11 Checking: 1110112 / 1012 = 5910 / 510 ≅ 1011.112 = 58.7510
1.12
(a) 10000 and 110111 1011 +101 10000 = 1610
1011 x101 1011 1011 110111 = 5510
(b) 62h and 958h 2Eh +34 h 62h
1.13
0010_1110 0011_0100 0110_0010 = 9810
2Eh x34h B 38 2 8A 9 5 8h = 239210
(a) Convert 27.315 to binary:
27/2 = 13/2 6/2 3/2 ½
Integer Quotient 13 6 3 1 0
Remainder + + + + +
½ ½ 0 ½ ½
Coefficient a0 = 1 a1 = 1 a2 = 0 a3 = 1 a4 = 1
Digital Design With An Introduction to the Verilog HDL – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2012, All rights reserved.
Full file at https://testbankuniv.eu/Digital-Design-5th-Edition-Mano-Solutions-Manual
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2710 = 110112 .315 x 2 .630 x 2 .26 x 2 .52 x 2
= = = =
Integer 0 1 0 1
+ + + +
Fraction .630 .26 .52 .04
Coefficient a-1 = 0 a-2 = 1 a-3 = 0 a-4 = 1
.31510 ≅ .01012 = .25 + .0625 = .3125 27.315 ≅ 11011.01012 (b) 2/3 ≅ .6666666667 .6666_6666_67 x 2 .3333333334 x 2 .6666666668 x 2 .3333333336 x 2 .6666666672 x 2 .3333333344 x 2 .6666666688 x 2 .3333333376 x 2
Integer = 1 = 0 = 1 = 0 = 1 = 0 = 1 = 0
+ + + + + + + +
Fraction .3333_3333_34 .6666666668 .3333333336 .6666666672 .3333333344 .6666666688 .3333333376 .6666666752
Coefficient a-1 = 1 a-2 = 0 a-3 = 1 a-4 = 0 a-5 = 1 a-6 = 0 a-7 = 1 a-8 = 0
.666666666710 ≅ .101010102 = .5 + .125 + .0313 + ..0078 = .664110 .101010102 = .1010_10102 = .AA16 = 10/16 + 10/256 = .664110 (Same as (b)). 1.14
` 1.15
(a)
0001_0000 1s comp: 1110_1111 2s comp: 1111_0000
(b)
0000_0000 1s comp: 1111_1111 2s comp: 0000_0000
(c)
1101_1010 1s comp: 0010_0101 2s comp: 0010_0110
(d)
1010_1010 1s comp: 0101_0101 2s comp: 0101_0110
(e)
1000_0101 1s comp: 0111_1010 2s comp: 0111_1011
(f)
1111_1111 1s comp: 0000_0000 2s comp: 0000_0001
(a)
25,478,036 9s comp: 74,521,963 10s comp: 74,521,964
(b)
63,325,600 9s comp: 36,674,399 10s comp: 36,674,400
(c)
25,000,000 9s comp: 74,999,999 10s comp: 75,000,000
(d)
00000000 9s comp: 99999999 10s comp: 100000000
1.16 15s comp: 16s comp: 1.17
C3DF 3C20 3C21
C3DF: 1100_0011_1101_1111 1s comp: 0011_1100_0010_0000 2s comp: 0011_1100_0010_0001 = 3C21
(a) 2,579 → 02,579 →97,420 (9s comp) → 97,421 (10s comp) 4637 – 2,579 = 2,579 + 97,421 = 205810 (b) 1800 → 01800 → 98199 (9s comp) → 98200 (10 comp) 125 – 1800 = 00125 + 98200 = 98325 (negative) Magnitude: 1675 Result: 125 – 1800 = 1675
Digital Design With An Introduction to the Verilog HDL – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2012, All rights reserved.
Full file at https://testbankuniv.eu/Digital-Design-5th-Edition-Mano-Solutions-Manual
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Full file at https://testbankuniv.eu/Digital-Design-5th-Edition-Mano-Solutions-Manual
(c) 4,361 → 04361 → 95638 (9s comp) → 95639 (10s comp) 2043 – 4361 = 02043 + 95639 = 97682 (Negative) Magnitude: 2318 Result: 2043 – 6152 = -2318 (d) 745 → 00745 → 99254 (9s comp) → 99255 (10s comp) 1631